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The following equilibrium constants have been determined for oxalic acid at $25^{\circ} \mathrm{C}:$$$\begin{array}{r}\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{HC}_{2} \mathrm{O}_{4}^{-}(a q) \\\mathrm{K}_{\mathrm{c}}^{\prime}=6.5 \times 10^{-2} \\\mathrm{HC}_{2} \mathrm{O}_{4}^{-}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q) \\K_{\mathrm{c}}^{\prime \prime}=6.1 \times 10^{-5}\end{array}$$Calculate the equilibrium constant for the following reaction at the same temperature:$$\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q) \rightleftharpoons 2 \mathrm{H}^{+}(a q)+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q)$$

$$K_{c}=4.0 \times 10^{-6}$$

Chemistry 102

Chapter 14

Chemical Equilibrium

Rice University

Drexel University

University of Kentucky

Lectures

10:03

In thermodynamics, a state of thermodynamic equilibrium is a state in which a system is in thermal equilibrium with its surroundings. A system in thermodynamic equilibrium is in thermal equilibrium, mechanical equilibrium, electrical equilibrium, and chemical equilibrium. A system is in equilibrium when it is in thermal equilibrium with its surroundings.

00:54

In chemistry, chemical equilibrium (also known as dynamic equilibrium) is a state of chemical stability in which the concentrations of the chemical substances do not change in the course of time due to their reaction with each other in a closed system. Chemical equilibrium is an example of dynamic equilibrium, a thermodynamic concept.

02:30

The following equilibrium …

02:36

01:52

03:00

Oxalic acid is a relativel…

06:09

02:15

The equilibrium constant f…

So you want to find the equilibrium constant Casey for the following balance equation. So to do so we're going to use some information that we got from the problem itself. So we know that this fallen equation that I'm writing here has an equilibrium, constant value that is equivalent to 6.5 times 10 to the negative too. And this has some of the species that we need to see in this equation, but not all. So we're going to also use the second that we were given, which is as follows 24 C h plus plus see to oh, four tu minus. And this has an equilibrium constant value equivalent to 6.1 times 10 to the native five. So now between these two balance equations, we have all of the substances that we want to see in this equation that we were looking for, equal of room, constant value off. So we look at these, we can cross this out and this out since they're on opposite sides of these two equations and we can buy in these they seem that are entirely balanced. Equation between these two is exactly what we have wanted. to find the equal room constant here. So since always did to get to here was add these two together to find the eagle ever constant. All we had to dio is multiply the two equilibrium, constant values together and we find we simplify this and complete the calculation that the equilibrium constant Is it willing to four times 10 to the NATO six.

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