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Chapter 14, question 110.
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The following mechanism has been proposed for a gas -phase reaction of chloroform and chlorine.
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Now, what's the overall reaction? so to be able to do that, i want to add all these three steps, and left -hand sides to the left -hand sides, right -hand sides to the right -hand sides.
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So let's start.
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Cl2 plus cll plus chcl3 plus chcl3 plus cl plus cl plus cl plus ccl plus ccl 3.
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These are all left -hand sides.
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And right -hand sides, 2cl plus hcl plus ccl plus ccl 3 plus ccl 4.
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Now, if you want to rearrange these, what we have is ccl 3 over here, a ccl 3 over here, so they cancel.
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Do we have ccl4? we don't.
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Do we have 8cl? we don't.
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We have 2 cl on the right hand side, and we have 2 cl on the left hand side.
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So they cancel to you.
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So overall, what we're going to get is cl2 plus chcl3, which go to 8cl plus ccl plus ccl4.
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Now, what are the intermediates in the mechanism? so the intermediates are each elementary step, we get something at the products, and if that whatever we get in the products is consumed in the other elementary step, that is an intermediate.
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So chlorines over here are the intermediates, since we get them in the products and we consume them later on.
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Over here, we use get a ccl3 over here in the products and we consume that too.
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So ccl3 is also an intermediate.
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So this is part a and part b would be ccl3 and cl.
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Part c.
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Part c, what is the molecularity of each of the elementary reactions? so the molecularity of this first one is going to be unimolecular.
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The reason why is this is only one molecule.
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And the second one is going to be there are two molecules...