00:01
This is problem 91 from chapter 16, and we are trying to find the right for circle to over here on the right.
00:10
So the first circle on the left, it has six black, and your textbook says five orange.
00:18
I don't get orange as a color on here, so i'm using red.
00:23
And on the right side, number two, we have seven black and eight orange in this case, red.
00:28
So each sphere is .01 mole, and the volume of the circle is .5 liters.
00:36
So they do give us the initial rate for the first one.
00:39
So the initial rate for 1 is 8 .3 times 10 to negative 4 moles per liter times minute.
00:58
So we are trying to find the initial rate for 2.
01:02
So we're going to use this equation, which is the rate.
01:12
Excuse me.
01:13
You guys know what the rate equation is.
01:15
It's an other question.
01:16
So r is equal to k as a concentration of a, m, it's a concentration of b.
01:37
So in our case, we are going to make the a molecules, the black ones, and the b molecules, the orange slash red ones.
01:49
So we are going to find the molarity for the concentration of a.
01:56
So this is for the first circle, so one.
02:01
So concentration a is move to moles over liters.
02:10
And they said each dot is 0 .01 moles.
02:14
So we have six black ones.
02:16
So that is six times 0 .01.
02:23
0 moles and the volume is 0 .5 liters over 0 .5 liters...