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The following numbers are the ratios of second ionization energy to first ionization energy:Na: $9.2 \quad P: \quad 1.8$$\begin{array}{llll}\text { Mg: } & 2.0 & \text { S. } & 2.3\end{array}$Al: $3.1 \quad$ Cl: 1.8Si: $2.0 \quad$ Ar: 1.8
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Ionization energy is the energy required to remove an electron from an atom or ion. The first ionization energy is the energy required to remove the first electron, and the second ionization energy is the energy required to remove the second electron. Show more…
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The following numbers are the ratios of second ionization energy to first ionization energy: $\begin{array}{lllll}{\mathrm{Na} :} & {9.2} & {\mathrm{P} :} & {1.8} \\ {\mathrm{Mg} :} & {2.0} & {\mathrm{S} :} & {2.3} \\ {\mathrm{Al} :} & {3.1} & {\mathrm{Cl} :} & {1.8} \\ {\mathrm{Si} :} & {2.0} & {\mathrm{Ar} :} & {1.8}\end{array}$ Explain these relative numbers.
The following numbers are the ratios of second ionization energy to first ionization energy: Na: 9.2 Mg: 2.0 Al: 3.1 Si: 2.0 $P: 1.8$ $\mathbf{S}: 2.3$ Cl: 1.8 $\mathrm{Ar}: 1.8$ Explain these relative numbers.
Arrange these elements according to first ionization energy: Highest ionization energy Ar Cl Si Al Mg Na
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