00:01
So you have a list of six numbers and you want to construct a 90 % confidence interval.
00:08
And so this will end up being the x bar plus or minus a t value with .05 in the upper tail and it will have five degrees of freedom since your sample size here is six.
00:22
And then we'll multiply that by the sample standard deviation divided by the square root of n which will be six.
00:28
And i'm going to use my software and make the t interval for this data and then we'll answer the question.
00:36
But that is the formula that you would use in order to find this.
00:43
And so the first interval for the 90 % confidence interval is 3 .12 to 6 .8 and it would round to 8.
00:55
Now on part b we want a 95 % confidence interval.
00:58
And the only thing that's going to change is that t value will become .025 and we'll have still five degrees of freedom.
01:07
And so stat, test, that t interval, changing that level of confidence to .95, that interval becomes 2 .61 to 7 .39.
01:26
And we see that as we increase the confidence level we make the sample, the width of the interval change and become larger.
01:35
So next one, the 99 % confidence interval, again, that will be a t value with .005 in the upper tail and still five degrees of freedom.
01:45
So stat, test, interval, t interval, and change that to .99.
01:52
And again, if you have to show that longhand you can go through and show those steps.
01:55
1 .25 out to 8 .75.
02:02
Now part d says assume that the sample mean and sample standard deviation remain the same as calculated above, however, we have a sample size of 25.
02:12
And so that will end up being that you'll end up having that x bar was 5 and you're going to have plus or minus and you're going to have the 2 .28 or the standard deviation, but now it's going to be divided by the square root of 25 rather than the square root of 6...