Let's denote it as C6H5COCH3. Upon reaction with a base, it abstracts a proton from the methyl group, forming an enolate ion. This can be represented as follows:
\[ \text{C6H5COCH3} + \text{B}^- \rightarrow \text{C6H5COCH2}^- + \text{BH} \]
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