Question
The following solutions are mixed: $1.0 \mathrm{~L}$ of $0.00010 \mathrm{M}$ $\mathrm{NaOH}$ and $1.0 \mathrm{~L}$ of $0.0020 \mathrm{M} \mathrm{MgSO}_{4}$. Is a precipitate expected? Explain.
Step 1
Equal volumes (1.0 L + 1.0 L = 2.0 L) halve the initial concentrations. - [OH−] = 0.00010 M / 2 = 5.0×10−5 M. - [Mg2+] = 0.0020 M / 2 = 1.0×10−3 M. Show more…
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