00:01
In this question, we have to identify each species in these given reactions as either a bronze state lorry acid or a bronze state lary base.
00:12
For the first reaction, in the forward direction, cn minus accepts a proton and becomes hcn.
00:22
So cn minus is the bronze state lorry base.
00:26
Water donates a proton and becomes oh h minus.
00:30
So water is the bronzed lorry acid.
00:35
In the backward reaction, h -c -n donates a proton and becomes cn -minus.
00:40
So, a -c -n is the bronch -lawi -ac acid.
00:44
And oh -1 accepts a proton and becomes water.
00:49
So, oh -h -1 is the bronze -strelory base.
00:52
For the second reaction, in the forward direction, h -co -3 -mineus accepts a proton and becomes h -2 -c -7.
01:01
Co3.
01:02
So hco3 minus is the base.
01:06
H2 -s -o -4, donates a proton and becomes h -s -o -4 minus.
01:11
So h -2 -s -4 is the bronze -stad -lowry acid.
01:15
In the backward direction, h -s -o -4 minus accepts a proton and becomes h -2 -s -o -4.
01:22
So h -s -o -4 minus is the bronstade -lowdy base.
01:26
And h -2 -c -o -3, donates a proton and becomes h.
01:30
Co3 minus...