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Hello everyone.
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Let us see the following question.
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The following table gives the results of four electrophilic substitution reactions of chlorobenzing.
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So let us see the table given in the question.
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So these are the different substitution products, say chlorination product, nitration product, gromination and salponation product.
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At position 2 and 3 and 4, the percentages are also showing different.
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This is at position 2 substitution that is ortho substitution.
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If it is at position 3 that is called meta substitution, and also in position 4 it is called as para substitution.
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So, now that we are talking about the substitution of chlorobenzene.
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Let us see why these substitutions are favorable like this.
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So, this is the benzene and it is having chlorine.
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So, chlorine has the three lone pairs of electrons.
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So, hence, it is able to relocate the pair of electrons in delocalization.
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So, as we see here due to the delocalization, the electron composition comes to be at position two.
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So, at position two as well as position two, sorry, position four electron density increases.
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So, at 2 comma 4 electrons density increases.
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Hence, cl group is called as orthopara activator.
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Orthopara activating group or orthopara activators.
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At the same time, cl has the highly electronegative.
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It is due to highly electronegativity, negative behavior.
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It also shows minus i effect.
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So due to minus i effect, so the electron has a very small tendency to come to position 3.
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This percentage is very less of course.
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So if it is at position 3, it is called as metta.
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It is meta activator.
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It is meta activators.
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So, suppose if we are talking about sulfonation or chlorination, so if it is chlorination, so chlorination happens in the presence of chlorine in the presence of louis acid fecl3, which would generate a electrophile cl plus.
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If it is nitration, if it is nitration, we use a nitrating mixture that is concentrated hno3.
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Hno3 and concentrated h2, s .o4, which would generate a nitrogenium n -o2 plus...