The following table lists temperatures and specific volumes of water vapor at two pressures:
\begin{tabular}{ccccc}
\hline$p=1.0 \mathrm{MPa}$ & & \multicolumn{2}{c}{$p=1.5 \mathrm{Mpa}$} \\
\cline { 1 - 2 } \hline$\left({ }^{\circ} \mathrm{C}\right)$ & $v\left(\mathrm{~m}^{3} / \mathrm{kg}\right)$ & & $T\left({ }^{\circ} \mathrm{C}\right)$ & $v\left(\mathrm{~m}^{3} / \mathrm{kg}\right)$ \\
\hline 200 & $0.2060$ & 200 & $0.1325$ \\
240 & $0.2275$ & 240 & $0.1483$ \\
280 & $0.2480$ & 280 & $0.1627$ \\
\hline
\end{tabular}
Data encountered in solving problems often do not fall exactly on the grid of values provided by property tables, and linear interpolation between adjacent table entries becomes necessary. Using the data provided here, estimate
(a) the specific volume at $T=240^{\circ} \mathrm{C}, p=1.25 \mathrm{MPa}$, in $\mathrm{m}^{3} / \mathrm{kg}$.
(b) the temperature at $p=1.5 \mathrm{MPa}, v=0.1555 \mathrm{~m}^{3} / \mathrm{kg}$, in ${ }^{\circ} \mathrm{C}$.
(c) the specific volume at $T=220^{\circ} \mathrm{C}, p=1.4 \mathrm{MPa}$, in $\mathrm{m}^{3} / \mathrm{kg}$.