Question
The force acting between two point charges kept at a certain distance is $\mathrm{F}_{1}$ Now magnitude of charge are double and distance between them is double. The force acting between them is $\mathrm{F}_{2}$ find out the ratio of $\mathrm{F}_{2} / \mathrm{F}_{1}=\ldots \ldots \ldots \ldots \ldots$(a) $16: 1$(b) $1: 16$(c) $1: 1$(d) $1: 8$
Step 1
Mathematically, it can be expressed as: \[F_1 = k \frac{q_1 q_2}{r^2}\] where \(F_1\) is the force between the charges, \(k\) is Coulomb's constant, \(q_1\) and \(q_2\) are the charges, and \(r\) is the distance between the charges. Show more…
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