We can do this using the given angles and the force magnitude of $30N$. The components are given by $F_i = F\cos(\alpha)$, $F_j = F\cos(\beta)$, and $F_k = F\cos(\gamma)$. Substituting the given values, we get $F_i = 30\cos(60^\circ)$, $F_j = 30\cos(60^\circ)$,
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