Problem

Meters (a) By how many percent is the torque of …

05:16

Problem 40 Medium Difficulty

The force on the rectangular loop of wire in the magnetic field in Figure 22.62 can be used to measure field strength. The field is uniform, and the plane of the loop is perpendicular to the field. (a) What is the direction of the magnetic force on the loop? Justify the claim that the forces on the sides of the loop are equal and opposite, independent of how much of the loop is in the field and do not affect the net force on the loop. (b) If a current of 5.00 $\mathrm{A}$ is used, what is the force per tesla on the 20.0 -cm-wide loop?
Figure 22.62 A rectangular loop of wire carrying a current is perpendicular to a magnetic field. The field is uniform in the region shown and is zero outside that region.
22.8 Torque on a Current Loop: Motors and

Answer

Part (a): The force on the loop is directed downwards.
Part $(\mathrm{b}) :$ The force per tesla is 1 $\mathrm{N} / \mathrm{T}$ .

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Physics 102 Electricity and Magnetism

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Chapter 22

Magnetism

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Video Transcript

Q. For party, we're using right hand rule as in order to find the direction of the Net force. And here on each three sides of the rectangular wire, the force is exerted. We know that the magnitude of the force in both sides of the wire is the same because the magnetic field is uniform for the entire area. Um, we know that the same magnitude of current is flowing through the wires. And, of course, the angle between the current and the field is the same for both, for all that, for the entire all the wires. And however using the right hand rule here because the direction of current is opposite, um, by the right hand rule, the direction of the force is gonna be opposite. So here, therefore, the net force exerted on the sides of the loop are always equal and opposite to each other. And since they cancel out, we have no net force affected on the sides of the loop. Now, buy right hand rule. The current on the third side here is in the east. Or we can say to the right, uh, and and so the right thumb. You're right. Using right hand rolled the right family point towards the right, and the magnetic field is pointing out of the page. So the fingers, you're right. Fingers are pointing out of the page. And so the palm is going to be pointing down or south. So here we can say bye, right hand rule being net force is down or to the south, that would be your answer for part a four part B. We're simply using the formula f this equaling the magnitude of the magnetic field times, the current times, the length, times sign of data and we can say a force Overby so forced perv magnetic field. Or this would be essentially Newtons per Tesler. This would be equaling the current times l the length time sign of Fada. And so we can say that F Overby would equal 5.0 amps multiplied by the length of 0.200 meters multiplied by sine of 90 degrees. And this is gonna be equaling 1.0 Newtons per Testa. This would be our force, Per Tesla. That is the end of the solution. Thank you for watching

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