Question
The freezing point of a $5 \%$ solution of eucatropine hydrochloride is $-0.55^{\circ} \mathrm{C}$. How many grams of eucatropine hydrochloride should be used in preparing $100 \mathrm{~mL}$ of an isotonic solution?
Step 1
The molecular weight of eucatropine hydrochloride can be calculated as follows: (18 x 12.01) + (28 x 1.01) + 35.45 + 14.01 + (2 x 16.00) = 339.45 g/mol Show more…
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