00:01
So, given in the question, the frequency of vibration of a vibrating string is given as f that is equals to 1 by 2l under root t by rho, where l is the length of the string, t is the tension in the string and rho is the linear density of the string.
00:37
Now, it has been asked to find the rate of change of the frequency of vibration as a function of the length of the string, keeping the tension and linear density constant.
00:59
In the second part, it is asked to find the rate of change of frequency with respect to tension, keeping l and rho constant.
01:10
And in the third part is to find the rate of change of frequency as a function of linear density, keeping l and t constant.
01:20
In part b, it has been asked that what happens to the pitch when in the first case, the effective length of the string is decreased.
01:32
In the second case, when the tension in the string is increased.
01:40
And in the third case, the linear density of the string is increased.
01:54
So, solving the first part, part a and the first part of part a.
02:01
So, taking the derivative of f with respect to l keeping t and rho constant.
02:06
So, we can take out t and rho out of the derivatives.
02:12
So, it is 1 by 2 root over t by rho d by dl of 1 by l.
02:19
So, d by dl of 1 by l is minus 1 by l square.
02:25
So, it would be 1 by 2 root t by rho times minus 1 by l square.
02:32
Finally, we are getting df by dl to be minus 1 by 2 l square under root t by rho.
02:41
Now, in the second is to find the rate of change of f with respect to t, keeping l and rho constant.
02:49
So, we can take out l and rho out of the derivative sign and find the derivative of root t with respect to t.
02:59
That value is 1 by 2 root t...