00:01
So here we see that the point 62 lies on the graph of, well, y1.
00:07
And the second view shows of the function, well, y2 is the square root function, and it is shifted two units to the right.
00:20
So the point 6 negative 1 here lies on the graph of, well, y2.
00:26
Okay, so from the point 6 -2 on the graph of y1, we observe that when x is 6, right, y1 is 2.
00:37
So this means that the equation of the function, y1 is defined as, so we have y1 is defined as the square root of x minus 2.
00:54
And we have that, well, y2 is x minus 2 plus k.
01:02
So we have y2 is equal to the square root of x minus 2 plus k...