Question
The functions $u=e^{x} \sin x, v=e^{x} \cos x$ satisfy the equation(a) $v \frac{d u}{d x}-u \frac{d v}{d x}=u^{2}+v^{2}$(b) $\frac{d^{2} u}{d x^{2}}=2 v$(c) $\frac{d^{2} v}{d x^{2}}=-2 u$(d) All of these
Step 1
$\frac{du}{dx} = \frac{d}{dx}(e^x \sin x) = e^x \sin x + e^x \cos x = u + v$ $\frac{dv}{dx} = \frac{d}{dx}(e^x \cos x) = e^x \cos x - e^x \sin x = v - u$ Now let's check each option: Show more…
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