00:01
Hi everyone, i'm here with problem 14 from chapter 7.
00:04
In this problem, we're given two different bonds, and we're given certain characteristics about these bonds.
00:12
In a, we're told that this bond has a wavelength of 9 .6 micrometers, and we're asked to find the frequency.
00:20
While in b, we're told that the bond has a frequency of 8 .652 times 10 to the 13th hertz, and we're asked to find the wavelength.
00:29
So first before we solve, let's find a relationship between wavelength and frequency.
00:39
So we know that the speed of light, which will represent as c, is equal to the frequency times the wavelength.
00:51
So this is our relationship that we can use to solve for our frequency and wavelength.
00:57
So let's start with a.
01:00
We need the frequency, so let's rearrange this equation to solve for the frequency.
01:05
So we can say that new is equal to c divided by lambda.
01:16
And we know c is just the speed of light, which is 3 times 10 to the 8 meters per second...