Question
The G string on a guitar is $59 \mathrm{cm}$ long and has a fundamental frequency of 196 Hz. A guitarist can play different notes by pushing the string against various frets, which changes the string's length. The first fret from the neck gives $A b(207.65 \mathrm{Hz})$ the second fret gives $\mathrm{A}(220 \mathrm{Hz}) .$ How far apart are the first and second frets?
Step 1
In the fundamental mode of vibration, the length of the string is half the wavelength, so we can write $\lambda = 2L$. Substituting the given values, we get \[v = f \cdot 2L = 196 \cdot 2 \cdot 0.59 = 231.28 \, \text{m/s}.\] Show more…
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The G string on a guitar is 59 cm long and has a fundamental frequency of 196 Hz. A guitarist can play different notes by pushing the string against various frets, which changes the string's length. The first fret from the neck gives Ab (207.65 Hz); the second fret gives A (220 Hz).
The G string on a guitar is 59 cm long and has a fundamental frequency of 196 Hz. A guitarist can play different notes by pushing the string against various frets, which changes the string's length. The seventh fret from the neck gives D (293.66 Hz); the eighth fret gives Eâ™ (311.13 Hz). How far apart are the seventh and eighth frets? Express your answer to two significant figures and include the appropriate units.
The G string on a guitar is 64 cm long and has a fundamental frequency of 196 Hz. A guitarist can play different notes by pushing the string against various frets, which changes the string's length. The third fret from the neck gives Bb (233.08 Hz) and the fourth fret gives B (246.94 Hz). How far apart are the third and fourth frets? Please show work.
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