00:01
Hello everyone.
00:01
In this problem, we're asked to find out a couple of details about the transmitted gps signal of a satellite.
00:08
So we're told that the satellite is broadcasting in a downward hemisphere, and its radiation is incident on a square panel of side length l.
00:20
And we're asked to find what the intensity is that this panel sees, what are the electric and magnetic field amplitudes that the position? of the panel.
00:32
How long does the signal take to reach the panel? what pressure does the radiation exert on the panel? and what wavelength the panel has to be tuned to in order to absorb the radiation coming from the satellite.
00:47
Okay, so here we're given a bunch of details.
00:50
We're told that the satellite is transmitting at a frequency or half of its power is transmitted at a frequency of 1575 .42 times the other 6 hz.
01:02
And we're told that the total power output is 50 watts and that it is split equally between the two frequencies at which it radiates, its electromagnetic radiation or signal.
01:12
And so the power of this wave with this given frequency is 25 watts.
01:18
We're told what the length of the side of the panel is, which eventually we're not going to use.
01:24
And then we're told that the satellites orbit the earth such that they make two revolutions a day around the surface of the earth, which means that the period for one revolution is half a day or 12 hours, which is 4 .32 times 10 to 4 seconds.
01:40
And then here, i've just collected a bunch of constants that we need to look up in order to complete our calculations, which are details about the earth.
01:48
So it has a mass of 5 .97 times 1024 kilograms, a radius of 6 .37 times 10 to 6 meters.
01:57
And newton's constant is 6 .67 times the 13 units meter squared per kilogram squared.
02:03
And then a bunch of other constants like speed of light and the primitivity of free space.
02:08
Okay, so what is the intensity? that's the first question that we have to ask.
02:13
And so the intensity is the radiated power divided by the area.
02:17
And because we are only, the satellite is only emitting its radiation in a downward hemisphere, which means that it's only half a sphere.
02:25
So the area of that hemisphere or half hemisphere is 2 pi times l squared, where l is the distance above the surface of the earth, whereas what we're going to be able to calculate using newton's second law and newton's gravitational law, the inverse square law is the distance between the center of the earth and the satellite.
02:47
But then using the radius of the earth, we can subtract that and we can find the altitude.
02:53
So how do we do that? well, we see that the forces on the satellite have to be equal.
02:58
So, or we have to say that the irritation, we have to set the gravitational force on the satellite equal to the force that is required for it to stay in orbit, which means that when it's going through centripetal motion, it has to have an acceleration that is v squared over r, where r is the distance between the two center of gravities or the two center of masses of the two objects.
03:25
And so we have for the force, g, mass of the satellite times mess of the earth over r squared is equal to mess of the satellite times v squared over r.
03:35
So this is just the consequence of circular motion.
03:40
And so v, what's the velocity? the velocity is 2 pi r divided by the period, which is, you know, it's just to say that in a circular motion, in one period, the object travels around one surface.
03:54
Which is equivalent to a distance of 2 pi times r...