the-graph-above-is-the-position-versus-time-graph-of-an-object-which-of-the-following-is-the-veloc-2

Name: the graph above is the position versus time graph of an object which of the following is the veloc 2
Uploaded: 2019-08-28
Duration: 33 s
Channel: Numerade
Description: The graph above is the position-versus-time graph of an object. Which of the following is the velocity-versus-time graph of the object?

Question

The graph above is the position-versus-time graph of an object. Which of the following is the velocity-versus-time graph of the object?

Salamat Ali · Accepted Answer

from the position Time graph we see at the position. Off object. So this is a position time. Grab the position. Often object is decreasing. Decreasing Engaged to zero. So the object he must be moving in a negative direction with slower eight. Therefore, the last will be negative initially. So the option D is the right answer. Option D End of the problem. Thank you for watching.

Riley Scott Jacob · Answer

imagine we have some position. Time graph X against T showing the trajectory through space over time of some object except E How can we use this position Time graph to determine the objects velocity, the instantaneous velocity or specifically at any point in its history. Well, what is average velocity over a time interval, Of course, given by the change in position over that time interval divided by the time interval itself. So if we take se this to be our starting point and this to be our ending point, then we would can observe that this distance this quote unquote horizontal change is our delta t and this distance, this quote unquote vertical change is our adult toe X And because we know that velocity is Delta X divided by delta t, we see that the velocity in this case would simply be this distance divided by this distance. But what are we actually doing here? Well, the variable names may be obscuring it a little, but this should be familiar. Imagine you had a normal Cartesian X Y coordinate plain as you&#x27;re probably used to, and you had some curve on it and you wanted to find the slope of a line between two points on this curve. How would you do so? Well, course we would just say that I m is the change and why divided by the change in axe and that&#x27;s exactly what we&#x27;re doing over here too. It&#x27;s simply that our quote unquote why access in this case is the objects position and the quote unquote x axis in this case is the time. And so the change in X, divided by the change in time on a position of time graph, gives off objects velocity much the same way that Delta y over Delta X on a typical Cartesian coordinate plan gives us the slope. But graphically, what this implies is that an objects velocity on a position time graph is the slope of the position time graph at that point. So, for example, if we&#x27;re talking about this point here than this, the slope of that point would be the objects velocity there and similarly, at any other point, say this one here the objects velocity. That point would be the slope there. Um, so the instantaneous velocity of an object based on its position time graph can be found as the slope of the P T graph. At that point

Surjit Tewari · Answer

questionable tied a three. The velocity were says, I&#x27;m graph is given us like this year. Velocity is constant and then it is decreasing, becomes negative and again becomes constant. No, the position versus time graph for this will be the position. Were says time ground. The position increases becomes nearly constant and then again it decreases.

Salamat Ali · Answer

from the given position. Worse is position worsens. Time graph. We learned that the the solution is a constant. The object is moving in negative direction. So is the right option. And we also see that the speed off the object is a decreasing. So do you use the right option? Um

Kristela Garcia · Answer

so the problem asks us to determine which of the following position time grafts have constant negative acceleration. So if we look at our poor choices, we know for sure A and be have to be out because both of these show constant acceleration. It was our constant velocity, which translates to an acceleration of zero. So those two are automatically out. And if we look at the next to this first graph is moving in the negative direction and slowing down, which means its acceleration must be in the opposite direction, which in this case would be positive if we look at the next graph. This is also moving in the negative direction, but it is speeding up, which means it&#x27;s acceleration must be in the same direction. So this one shows an acceleration off that&#x27;s negative.

Ze-Han Lee · Answer

All right. So the slope of ah, um uh, velocity time diagram. So that will be data be over that a t in the limit. Ah, that&#x27;s equal zero Ray. So this is the definition of acceleration, all right?

Problem

Refer to the following diagram and paragraph. Gly…

Problem 4 Medium Difficulty

The graph above is the position-versus-time graph of an object. Which of the following is the velocity-versus-time graph of the object?

Answer

Related Courses

Cracking The AP Physics 1 Exam

Related Topics

Discussion

Top Educators

Recommended Videos

Watch More Solved Questions in Chapter

Video Transcript

Princeton Review

Cracking The AP Physics 1 Exam

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

Cracking The AP Physics 1 Exam

Princeton ReviewCracking The AP Physics 1 Exam

Princeton Review

Cracking The AP Physics 1 Exam