Question
The graph of a quadratic function $f$ is given.a. Find the coordinates of the vertex and the $x$ - and $y$ -intercepts.b. Find the maximum or minimum value of $f$c. Find the domain and range of $f$$$f(x)=-\frac{1}{2} x^{2}-2 x+6$$
Step 1
Here, $a = -\frac{1}{2}$ and $b = -2$. So, the x-coordinate of the vertex is $-\frac{-2}{2(-\frac{1}{2})} = -2$. Substituting $x = -2$ into the function gives $f(-2) = -\frac{1}{2}(-2)^2 - 2(-2) + 6 = 8$. So, the vertex is $(-2,8)$. Show more…
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