00:01
In problem 12, we have the equation x equals 3y squared plus 6y plus 7.
00:06
And with this, we need to graph this and find the vertex.
00:11
So the first thing we know is that since we have that y -squared term, x -axis is the major axis, opens either to the left or to the right.
00:18
So we're looking to put this in the standard form of x is equal to a y -minus k squared plus h.
00:26
In order to do that, we're going to need to take the right -hand side, and we're going to need to complete the square.
00:32
And that's so we can find that h and k for our vertex, as well as the a, so you can easily identify the behavior of this graph.
00:40
So we have a is equal to, i'm going to put in parentheses this 3y squared plus 6y, that's what we're going to complete the square on, and outside of that we're going to have this constant of plus 7.
00:51
And we're going to have to balance this equation by kind of doing the opposite of whatever we add inside these parentheses.
00:57
We'll need to do the opposite of that outside the parentheses.
01:03
So we need to have a coefficient of 1 on the y.
01:07
So we are going to divide the whole parentheses by 3.
01:11
We're going to get y squared plus 2y.
01:15
Leave that gap there outside the parentheses plus 7.
01:20
So we can take, now complete the square, because we have that coefficient of 1 on the y squared.
01:25
So half of 2, the coefficient of the 1, the y is going to be one, square that, we're just going to have plus one.
01:33
And then we added one inside the parentheses.
01:36
Remember, the coefficient of the parentheses is three.
01:39
So we essentially added three times one to the right -hand side of the equation...