Question
The graph of $f(x)=-2(x-3)^2+5$ is a parabola that opens ________, with its vertex at $(\_\_\_,\_\_\_)$, and $f(3)=$ _______ is the (minimum/maximum) ________ value of $f$.
Step 1
The general form of a quadratic function is \( f(x) = a(x-h)^2 + k \). In this function, \( f(x) = -2(x-3)^2 + 5 \), the coefficient \( a \) is \(-2\). Since \( a \) is negative, the parabola opens downwards. Show more…
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