00:01
This question, the graph of x over lnx plus x is given.
00:04
So we need to find the coordinates of the minimum point.
00:06
So it looks something like this over here, but definitely we've got to use derivative, the property of the derivative.
00:13
So the first derivative is going to look like we've got to use the question root.
00:18
So we have the denominator square times the denominator.
00:24
We have denominator times differentiation of numerator, minus the numerator which is x times the differentiation of the denominator which is ln x plus x so that's going to be x plus ln x and the differentiation of x is just one minus x remains as it is and this is a differentiation of natural log of x is 1 over x and differentiation of x is just 1 over x plus lnx whole square so this becomes x plus ln x minus if we open up the parentheses x times 1 over x is just 1 and x x times 1 is just x so here we have x over x plus ln x whole square so if we simplify this this x and minus x is cancer and we have lnx minus 1 over here over 1 plus over x plus lnx whole square so in order to find the critical points we equate the derivative to 0 so we have f dash x equated to 0 this means that whenever a rational expression is equal equated to zero, this means that the numitor must be zero.
01:36
So we have lnx minus one equated to zero, which means that lnx is equal to one.
01:41
Taking antelaw, both sides, we have the value of x as e.
01:45
Using the first derivative test, let's try to find whether this has a maximum or minima.
01:49
So at e, the sign of the derivative, if it is less than e, then this value is going to be less than one...