the-graph-of-the-function-mathrmf-is-shown-at-the-right-a-mathrmf2-b-mathrmf-5-c-mathrmf-2-d-mathrmf

Question

The graph of the function $\mathrm{f}$ is shown at the right. 
a. $\mathrm{f}(2)$
b. $\mathrm{f}(-5)$
c. $\mathrm{f}(-2)$
d. $\mathrm{f}\left(3 \frac{1}{2}\right)$

Cory Kuzinski · Accepted Answer

all right. A few things we gotta figure out here. First off f of to All right. So at the input to right here, what&#x27;s our output? And that is also to for B f at negative five. So we got a negative five and work our way down, and we could see that the output would be negative. Three. What about? I guess I&#x27;ll do this one in red of Negative, too. So if I go to negative two and then work my way down, I could see my output. Right? There is also negative, too. One more f of 3.5. All right, So 3.5 is right here. Work our way up, and it is, too. I&#x27;ll put it to when our input is 3.5.

Heather Zimmers · Answer

Okay, so here we have a sketch of our graph and we want to graph y equals F of X minus three. So we&#x27;re going to take the original graph and shifted down three units, and I like to do that by taking the key points, the end points of the segments and shifting them down first. So the endpoints go down three and then we can connect them. And that&#x27;s our graph for part A. For part B, this transformation is going to be a shift left one. So I&#x27;m going to do the same kind of thing where I&#x27;m going to take the key points, the end points of the segments, and shift them, left one, and then connect them, and that will shift the entire graph left one. So that&#x27;s our graph for part B. And the transformation taking part in part C is a vertical shrink by a factor of two, so the graph will be half as tall. So what we&#x27;re going to do is take those key points and cut their Y coordinates in half. So if we have a point with a white coordinated to its now, gonna be one a point with a white coordinative zero. Still zero a point with a Y coordinate of three. Now that&#x27;s 1.5 and a point with a Y coordinate of two. Now that&#x27;s one. And then we connect those and we get a graph that&#x27;s half is tall. Same width noticed. No change to the width on lee. A change to the height Never part D. What we have here is a reflection about the Y axis. Excuse me about the X axis. Okay, so we&#x27;re going to take each of the key points and reflected across the X axis. So point at a height of two is now going to be a height of negative, too. A point at a height of zero is still zero a point at a height of three is now at negative three and a point at height of two is now negative too. And then we connect those points and we have our reflected graph

Ankit Gupta · Answer

look in this case, we just need to answer the question from the graph graph is already provided in the question. We just need to find these three values. What is f in was to what is the value off F? It was five on orders about leadoff F in verse six. Okay, so from the graph, this Y X is it was in this 60.25 and six and the x axis represent its corresponding value. So we just called for the first. But this is f in verse two. So the value of F in verse two that simply comes out to be This is six. OK, now the 2nd 1 says there is a value of f inverse five. So the value of F in verse five is equals to This is but okay on this is f inverse. Sixth, the value of life in Verse six is equals to some Presidio. So we have the values here. This is 61 and zero

Ankit Gupta · Answer

we have been given the graph or bicycle toe effects in part a. We have to find the value of the drop off by is equal to two times F of X plus five minus one. So first with every will do this in the in three steps. First, we will find the value off. Why is equal to affects less five now even shift ethics minus five units along XX ISS do get f off X plus five. Now in part two, we have toe find the value off two times F off X plus five since two is clearly greater than one. Therefore, we will stretch the obtained by bicycle to FX plus five graph by effected off. Don&#x27;t India along by excess direction in party, we have to find this minus one shift so this minus one is outside off this bracket. Therefore in party will shift the top 10 graph, which is two times f off express five minus one units along the right excess. Now in part B, we have to find the graph off. Why is equipped to one by four F Off X minus three plus five. So again, we will do this in three steps. So in step number one we will find the value of F off X minus three, so we will shift. Since this is a negative sign here, we will shift FX. Blessed three units along xx is don&#x27;t get f off X minus chief. No, in part to since one by four is clearly less than one. So we will shrink f off X minus tree by a factor off one by Ford along. Why excess To get when by Ford f o X minus t now in step number three. So this is plus five shift, therefore given shift led by four F x minus. T graph less five units along by excess. Thus, we will opt in this graph.

Amy Jiang · Answer

Okay, so for this question, you&#x27;re gonna want to bring up your book on birth for to, um, or graph that we&#x27;re looking at. But before we decide to refer to that, let&#x27;s start by Be Writing or falling are functions. So of course he is the same as F, evaluated on five plus G. Evaluated and dignified for a finest G. We have the same day, but now we have or difference, and we&#x27;re evaluating at it at three inside. No for our product that&#x27;s f evaluated at negative bidding Times G evaluated nothing Big three finalists for referred to Part eight. So let&#x27;s find our function or a function that&#x27;s our reddish graph. So at negative five, what is that&#x27;s equal to a three? And then what about RG Negative flies? That&#x27;s our blew up on. We have a negative three, so we have three plus negative three, and that&#x27;s equal to zero. Now let&#x27;s refer to port enough, so that&#x27;s or at our X is equal to three or F graph gives us in three and then at, um, G ex article three or green or blue graph is and they get a free. So we have 33 which is equal to Dio. Now let&#x27;s look, uh, port See at X is equal to negative three or ask is a one and RG is a negative three. So this gives us in a negative three.

Ankit Gupta · Answer

we have been given the graph for physical toe FX, and from that graph, we will have to opt in. Why is equal to one by three f off X minus to plus five. So first we will get f off X minus two. So we&#x27;ve been shift ethics two units to the right to get this. Why is it called F of X minus two now in part two. So we have to counter this one by three factors since one by trees clearly less than one. Therefore, we will shrink the often f off X minus two by a factor off one by tree along my excess delegate one by three F X minus two Now in step three, we have to factor in this plus five shift. So even shift went by three F off X minus two obtaining the step number two upwards plus five units to get this equation. No, In fight number B, we have to octane. Why is it called for F off X plus one less she so again, in step number one, even shift ethics one units left to get f off X plus one and step number two so four is clearly greater than but we will stretch F off X plus one by affected off would and by excess direction. Now in step number three, we will have affected this blustery shift, so we will shift the opt in four FX plus monograph in step number two plus three units up flights so we will get this graph.

Problem

The sales tax $t$ on a purchase is a function of …

Problem 15 Hard Difficulty

The graph of the function $\mathrm{f}$ is shown at the right.
a. $\mathrm{f}(2)$
b. $\mathrm{f}(-5)$
c. $\mathrm{f}(-2)$
d. $\mathrm{f}\left(3 \frac{1}{2}\right)$

Answer

a) $f(2)=2$
b) $f(-5)=-3$
c) $f(-2)=-2$
d) $f\left(3 \frac{1}{2}\right)=2$

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Ann Xavier Gantert

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a) $f(2)=2$b) $f(-5)=-3$c) $f(-2)=-2$d) $f\left(3 \frac{1}{2}\right)=2$

Algebra 2 and Trigonometry

Grace H.

Catherine R.

Caleb E.

Maria G.

Absolute Value - Example 1

Absolute Value - Example 2

Ann Xavier GantertAlgebra 2 and Trigonometry

Grace H.

Catherine R.

Caleb E.

Maria G.

a) $f(2)=2$
b) $f(-5)=-3$
c) $f(-2)=-2$
d) $f\left(3 \frac{1}{2}\right)=2$

Ann Xavier Gantert

Algebra 2 and Trigonometry