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The greatest height reported for a jump into an airbag is 99.4 $\mathrm{m}$ by stuntman Dan Koko. In 1948 he jumped from rest from the top of the Vegas World Hotel and Casino. He struck the airbag at a speed of 39 $\mathrm{m} / \mathrm{s}$ $(88 \text { milh. To assess the effects of air resistance, determine how fast he }$ would have been traveling on impact had air resistance been absent.
$v_{y}=-44.14 \mathrm{m} \cdot \mathrm{s}^{-1}$
Physics 101 Mechanics
Chapter 2
Kinematics in One Dimension
Motion Along a Straight Line
University of Michigan - Ann Arbor
University of Washington
Simon Fraser University
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we're told that a stuntman jumps a vertical distance of 99.4 meters, a record breaking distance into a, um, your bag and the initial velocity of the stuntman is zero. At the time of the jump, the final velocity was 39 meters per second. But we're asked to figure out what the final velocity would have been had there been no air resistance. So if we just use the acceleration due to gravity G as 9.80 meters per second squared this, would this would negate any air resistant effects. So we're gonna use the equation. V squared is equal to the initial squared, plus two times the acceleration, which is G times that displacement in the Y direction, which is what? So this is the same equation with used in the extraction. But now it's vertical. So we have a special acceleration, which is 9.80 and the why instead of X, because we're moving vertically. So we're looking for V, so we'll plug in. That B squared is equal to zero square plus two times 9.8 oh meters per second squared times 99.4 meters. So V squared is an equal to 1948.24 major square per second square. And if we take the square root of both sides, we get 44 0.14 meters per second. This problem has, uh, too sick pigs as the smallest number, so would be 44 meters per second, contrasting that to what the actual velocity waas with their resistance which is 39 meters per second, that was given in the problem.
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