00:02
Okay, this question asks us about this logistic growth model.
00:07
So we're given all the parameters for this distribution.
00:13
So all we have to do is write this in the form where a logistic equation is just the max population over 1 minus the quantity p max over p initial minus 1 times e to the p max times e to the p max times.
00:37
K times t so in our case the max population is 10 ,000 and filling in the other numbers we get 1 minus 49 e t and p max times k just gives us negative 0 .1 t so now we have our growth model so it wants the population and the rate at certain t values so to get the rate we're going to have have to find a derivative.
01:21
So g prime of t would be 10 ,000 times the derivative.
01:30
So we're taking the derivative of 1 minus 49e to the negative 0 .1 t to the negative 1 .1.
01:39
So we can just use the chain rule here and get 10 ,000 times negative 1 times 1 minus 49e to the negative 0 .1 t to the negative 2 power times the derivative of the inside, which should be a plus, rather, times 49e to the negative 0 .1t times 0 .1, that is.
02:32
Or, rewriting this, we get g prime of is equal to 10 ,000 times 49 times 0 .1 e to the negative 0 .1 t all over 1 plus 49 e to the negative 0 .1 t all squared.
03:03
So now we can find g and g prime at various values...