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Problem 14

The growth rate of the sunflower from day 14 to day

35 is nearly constant. On this interval, which of the

following equations best models the height $h,$ in

centimeters, of the sunflower $t$ days after it begins

to grow?

$$\begin{array}{l}{\text { A) } h=2.1 t-15} \\ {\text { B) } h=4.5 t-27} \\ {\text { C) } h=6.8 t-12} \\ {\text { D) } h=13.2 t-18}\end{array}$$

Answer

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SAT

SAT Practice Test # 6

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## Discussion

## Video Transcript

So for this one, it says we're looking for the growth rate, which we know the grow three. Anything that has to do with the ray is just a slope. We want to look between the interval of day fourteen in day thirty five. Stay fourteen is right here. A thirty five is right here. So we wantto take this line right here and find the slope. Felon. If you want to find a slope with the guy, we just have to find the light to minus y one over x to minus X one, which means we need to isolate to place. So here, I'm going to go ahead and oops. Okay, so then from here, moving a little bit up, we can see the points better. So then that point, it seems like look something like, let's say, about fourteen comma thirty nine and then the second point for thirty five. Let's say that one is roughly about thirty five comma one thirty two. So then I'm going to use those two points and plugged that into this equation. Is someone gonna get one thirty two minus thirty nine her thirty five over minus fourteen consume one. Thirty two minus thirty nine because ninety three, then thirty five minus fourteen is twenty one. And if I defied those, I get four point for three. So that's our slope. So we need to find something with something similar to that. So the slope that's somewhat most similar is four point five. So I'm going to be and we don't even have to check for the intercepts because all of these slopes are very different, so we don't have to check for the intercepts.

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