Question
The half-life of carbon-14 is 5715 years. What is its decay constant?
Step 1
The formula is given by: \[ T = \frac{\ln(2)}{k} \] where \( T \) is the half-life, \( k \) is the decay constant, and \( \ln \) is the natural logarithm. Show more…
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The half-life of a radioactive substance is the amount of time required for half its mass to decay. The half-life of carbon-14 is 5730 years. What is the continuous annual decay rate of carbon-14? Please type in the exact answer.
What is the half-life for the first-order decay of carbon-14? $$\left(\begin{array}{c}14 \\6 \end{array} \mathbf{C} \longrightarrow_{7}^{14} \mathbf{N}+\mathrm{e}^{-}\right)$$ The rate constant for the decay is $1.21 \times 10^{-4}$ year $^{-1}$.
If radioactive Carbon 14 has a half-life of approximately 5745 years, verify that its decay constant is -0.000121.
Exponential and Logarithmic Functions
Applications of Exponential and Logarithmic Functions
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