The decay constant is given by the formula $\lambda = \frac{0.693}{T_{\text{half}}}$, where $T_{\text{half}}$ is the half-life of the isotope. In this case, $T_{\text{half}} = 8.0$ days. So, we have
\[\lambda = \frac{0.693}{8.0} = 0.087 \text{ day}^{-1}.\]
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