Question
The half-life of nitrogen- 16 is 7 seconds. How long does it take for $100 \mathrm{mg}$ of nitrogen- 16 to be reduced to $6.25 \mathrm{mg} ?$
Step 1
25 mg. We can use the formula: Final amount = Initial amount * (1/2)^(number of half-lives) 6.25 mg = 100 mg * (1/2)^(number of half-lives) Divide both sides by 100 mg: 0.0625 = (1/2)^(number of half-lives) Now, we need to solve for the number of half-lives. Show more…
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