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The Handbook of Chemistry and Physics (http://openstaxcollege.org/l/16Handbook) gives solubilities of the following compounds in grams per 100 mL of water. Because these compounds are only slightly soluble, assume that the volume does not change on dissolution and calculate the solubility product for each.(a) BaSeO, 0.0118 g/100 mL(b) $\mathrm{Ba}\left(\mathrm{BrO}_{3}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O}, 0.30 \mathrm{g} / 100 \mathrm{mL}$(c) $\mathrm{NH}_{4} \mathrm{Mg} \mathrm{AsO}_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}, 0.038 \mathrm{g} / 100 \mathrm{mL}$(d) $\mathrm{La}_{2}\left(\mathrm{MoO}_{4}\right)_{3}, 0.00179 \mathrm{g} / 100 \mathrm{mL}$

a. $1.77 \times 10^{-7}$b. $1.6 \times 10^{-6}$c. $2.2 \times 10^{-9}$d. $7.91 \times 10^{-22}$

Chemistry 102

Chapter 15

Equilibria of Other Reaction Classes

Chemical Equilibrium

University of Maryland - University College

Brown University

University of Toronto

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love one. This is Ricky. And today we're working on a problem number 11. So we're given four different compounds that are slightly soluble in water and we have to calculate their GSP. Hi. So a be ex, you owe four The Sol ability of wheat. Zero 0.11 going elements into 100 no leaders. All right, So the Moeller soluble ity is equal to Saul ability and rams no leader over her more mass times 1000 milliliters. Her one more or per one leader, which is equal to 10.118 rounds. 100 rubles. The more mass of BSC of four is 200 80 points. Lead graham and multiply by our conversion factor. And he gets 0.0 Sure, Jim one Moeller. So then we write the disassociation equation. Yeah, dissolves into Really, um for it's too. So now we can write our Caspi equation in Caspian is equal to early on CEO for less too. They're both gonna have the same concentration because if we look at her, uh, it's a one on one Moeller ratio, so point for 21 million more times 0.4 to 1. And remember that, Millie, Malicious. 41 time. Send him on his three physical. So this and we get chaos PSB with 1177 times to accept. All right. Next really being exact. Same thing before. Um, hey, b r 03 two, which is partially hydrated the water. And this has a solid ability of 0.30 grams for leader. All right, so we're gonna be doing the same thing. First. Calculate malls are the concentration. I mean, 0.30 grams per 100. No leader. Ramallah mash Kaine's 1000 here. Yeah, to elections 0.73 more right. The association equation. And then our guest P equation. Hey, plus two i minus. And then square is they have to out in front, and you are a calculation 0.7 e molder barium. And then there's gonna be two times that because there's to be our free 2.73 There's two squared and we get cast B is equal to 1.6 times 10 to the negative six. Hi. Next up, we have ammonium magnesium. Yeah, well, and that's especially hydrated with a solid ability of one of 38 ramps for 100 millimeter. Um, make the same calculations as before. 138 times. Milliner muller Masters to a nine, You know, times 1000 milliliters over one leader. And we get a concentration of points. The reserve 13 Now I want to do our disassociation equation on h for G s for partially dissolves into an H for US museum. What's this for? My free right R K s b in each or and cheap ones too. S former. Honestly, hello again. Our concentration. And we get that CASS P is equal to 2.2 times tender than they have none. All right? And then, lastly, we have l A to no oh for three. Just 0.179 nine, not eight. Rams dissolves into 100 No leaders. It's just like the Miller concentration Miller masses. 7 57.7 Jamal Arms 1000 Mel Leader's leader. And this is equal to 0.0 hoser. Observe 0 to 36 more. Now let's read our disassociation equation l a to and oh, for 30 dissolves into to l. A was three plus 30 04 minus two. Yes. Pierre is equal to too well. A waas, too Squared numbers three times three m 04 minus two. Cute for again and solve. Get case. Be a 7.91 times 10. 20 native. What if it is helpful and I'll see you in the next one?

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