Question
The hardness of water (hardness count) is usually expressed in parts per million (by mass) of $\mathrm{CaCO}_{3}$, which is equivalent to milligrams of $\mathrm{CaCO}_{3}$ per liter of water. What is the molar concentration of $\mathrm{Ca}^{2+}$ ions in a water sample with a hardness count of $175 \mathrm{mg} \mathrm{CaCO}_{3} / \mathrm{L} ?$
Step 1
Given that the hardness count is 175 mg/L, we can convert this to grams by using the conversion factor 1 g = 1000 mg. Therefore, the hardness count in grams per liter is $175 \times 10^{-3}$ g/L or 0.175 g/L. Show more…
Show all steps
Your feedback will help us improve your experience
Dr. Satish Ingale and 68 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The hardness of water (hardness count) is usually expressed in parts per million (by mass) of $\mathrm{CaCO}_{3},$ which is equivalent to milligrams of $\mathrm{CaCO}_{3}$ per liter of water. What is the molar concentration of $\mathrm{Ca}^{2+}$ ions in a water sample with a hardness count of 175 $\mathrm{mg} \mathrm{CaCO}_{3} \mathrm{L}$ ?
The hardness of water (hardness count) is usually expressed in parts per million (by mass) of CaCO3, which is equivalent to milligrams of CaCO3 per liter of water. What is the molar concentration of Ca2+ ions in a water sample with a hardness count of 175 mg CaCO3/L?
The hardness of water is usually expressed in parts per million (ppm) by mass of CaCO3. What is the hardness of a water sample with a Ca2+ ion concentration of 1.1Ă—10-3 M?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD