Question
The head light of a jeep are $1.2 \mathrm{~m}$ apart. If the pupil of the eye of an observer has a diameter of $2 \mathrm{~mm}$ and light of wavelength $5896 \AA$ is used what should be the maximum distance of the jeep from the observer if two head lights are just seem to be separated apart?(A) $30.9 \mathrm{~km}$(B) $33.4 \mathrm{~km}$(C) $3.34 \mathrm{~km}$(D) $30.9 \mathrm{~km}$
Step 1
The formula is given by: \[\theta = 1.22 \frac{\lambda}{D}\] where \(\theta\) is the minimum resolvable angle, \(\lambda\) is the wavelength of light, and \(D\) is the diameter of the aperture (in this case, the pupil of the eye). Show more…
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