00:01
To summarize the questions, so first of all, methane is being combust to release energy, and those energies are going to heat up and also boil one liter of water.
00:13
And then from there, we are required to find out the volume of the methane being combusted in the first place.
00:19
So in order to solve this question, first of all, we have to find out the total energy for heating up and boil that one liter of water.
00:27
Second, we have to find out the number of modes of methane.
00:30
And also the corresponding volume.
00:34
Okay, first of all, we are going to determine the total energy for first heating up.
00:43
And second, point the water, one liter of water.
00:47
We are given we have one liter of water in this question.
00:53
And we are also given the heat capacity of water is 75 .2 jouper mole per calvin.
01:00
So because the unit is in number of moles, so we have to further convert one liter of water to number of moles.
01:08
For the density of water, it's given that it's 1 gram per mill, mill, so for one liter of water, we will have 1 ,000 gram.
01:17
And by using the modern mass of water, we is corresponding to 80 gram per moles.
01:23
We are able to find out the number of most of water is 56 moles.
01:27
Okay, so the total energy, we will.
01:31
Release from the combustion of methane, we'll, part of the energy, we're first going to heat up water from 298 to feed 73k kelvin before boiling.
01:44
And the remaining energy will be going to boil one little water.
01:48
So first of all, let's find out the energy for heating up.
01:53
So the energy is fine by multiplying the number of modes, the heat capacity, and the different in the temperature...