00:02
In this problem, we're asked to consider the hydrogenation of naphthalene.
00:08
We're given a bunch of information here.
00:11
Let me get it down.
00:12
The heat of combustion for deca naphthalene, which is c -10, h -18.
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Let me make this a little bit more legible, is negative 6286 kilojoules per mole.
00:48
The heated combustion for naphthalene, which is c -10, h -181, is c -10.
01:01
10h8 is negative 5157 kilojoules per mole.
01:09
In both cases, the products are carbon dioxide and water.
01:24
Use the data that here and the data from the parenthood c find the heat of hydrogenation of naphthalene.
01:32
So we're finding the heat of hydrogenation of naphthalene.
01:38
So we're going to have three equations that we're going to use and we're going to combine two.
01:41
Then we can do one more first.
01:46
I'm going to leave my states off.
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Please remember that water will be this.
01:51
This is gas.
01:54
This is a liquid.
01:56
And this is a liquid.
01:58
So i'm going to start my equations.
03:26
Now we're subtracting this equation.
03:33
So what i'm going to get here is c10h8 plus 5 h2os on this side...