Question
The heat of solution of potassium acetate in water is $-15.3 \mathrm{kJ} / \mathrm{mol} \mathrm{KCH}_{3} \mathrm{COO} .$ What will be the final temperature when $0.241 \mathrm{mol} \mathrm{KCH}_{3} \mathrm{COO}$ is dissolved in $815 \mathrm{mL}$ water that is initially at $25.1^{\circ} \mathrm{C}$ ?
Step 1
Substituting the given values, we get: \[ q = 0.241 \, \text{mol} \cdot -15.3 \, \text{kJ/mol} = -3.68 \, \text{kJ} \] Show more…
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The heat of solution of potassium acetate in water is -15.3 kJ/mol KCH3COO. What will be the final temperature when 0.241 mol KCH3COO is dissolved in 815 mL water that is initially at 25.1 ºC
The heat of solution of potassium acetate in water is -15.3 kJ/mol KCH3COO. What will be the final temperature when 0.241 mol KCH3COO is dissolved in 815 mL water that is initially at 25.1 °C?
Heat of Solution The heat of solution of potassium acetate (KC2H3O2) in water is -15.30 kJ/mol. If 22.10 g of KC2H3O2(s) is dissolved in 575.0 mL of water that is initially at 24.80 °C, what will be the final temperature (in degrees Celsius) of the resulting aqueous solution? (Assume no heat exchange with the surroundings.) 26.23 °C
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