Question
The heat of vaporization of carbon tetrachloride, $\mathrm{CCl}_{4}$, is $29.9 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Using this information and data in Tables 18.3 and $18.4,$ estimate the standard heat of formation of liquid $\mathrm{CCl}_{4}$
Step 1
From Table 18.3, we have the following standard heats of formation: ΔHf°(C, graphite) = 0 kJ/mol ΔHf°(Cl2, gas) = 0 kJ/mol ΔHf°(CCl4, gas) = -95.7 kJ/mol The reaction for the formation of gaseous CCl4 is: C(graphite) + 2Cl2(gas) → CCl4(gas) Show more…
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Carbon tetrachloride, $\mathrm{CCl}_{4}$, is a liquid used as an industrial solvent and in the preparation of fluorocarbons. What is the heat of vaporization of carbon tetrachloride? $$ \mathrm{CCl}_{4}(l) \longrightarrow \mathrm{CCl}_{4}(g) ; \Delta H^{\circ}=? $$ Use standard enthalpies of formation (Table 6.2).
The following data are given for $\mathrm{CCl}_{4}:$ normal melting point $=-23^{\circ} \mathrm{C}$ normal boiling point $=77^{\circ} \mathrm{C}$ density of liquid $=1.59 \mathrm{~g} / \mathrm{mL}$ vapor pressure at $25^{\circ} \mathrm{C}=110 \mathrm{~mm} \mathrm{Hg}$ How much heat is required to vaporize $20.0 \mathrm{~L}$ of $\mathrm{CCl}_{4}$ at its normal boiling point?
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