Question
The height of a helicopter above the ground is given by $h$ $=3.00 t^{3}$, where $h$ is in meters and $t$ is in seconds. After $2.00 \mathrm{~s}$, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?
Step 1
00 t^{3}$. Substituting $t = 2.00 s$, we get $h = 3.00 \times (2.00)^{3} = 24.00 m$. Show more…
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The height of a helicopter above the ground is given by $h=3.00 t^{3},$ where $h$ is in meters and $t$ is in seconds. At $t=2.00 \mathrm{~s},$ the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?
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