Question
The height of the IDS Center in Minneapolis is $792 \mathrm{ft}$. Ignoring air resistance, use the formula $d=\left(\frac{16 \mathrm{ft}}{1 \mathrm{~s}^{2}}\right) t^{2}$ to find the time for an object to fall this distance. Round to the nearest hundredth. (Source: www.glasssteeland .com)
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The height of the IDS Center (d) is 792 ft. Show more…
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