The Henderson-Hasselbalch equation can be written as $$\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}-\log \left(\frac{1}{\alpha}-1\right) \text { where } \alpha=\frac{\left[\mathrm{A}^{-}\right]}{\left[\mathrm{A}^{-}\right]+[\mathrm{HA}]}$$ Thus, the degree of ionization $(\alpha)$ of an acid can be determined if both the $\mathrm{pH}$ of the solution and the $\mathrm{PK}_{\mathrm{a}}$ of the acid are known.
(a) Use this equation to plot the pH versus the degree of ionization for the second ionization constant of phosphoric acid $\left(K_{\mathrm{a}}=6.3 \times 10^{-8}\right)$
(b) If $\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}$ what is the degree of ionization?
(c) If the solution had a pH of $6.0,$ what would the value of $\alpha$ be?