The Hermitian adjoint of a complex $m \times n$ matrix $A$ is the complex conjugate of its transpose, written $A^{\dagger}=\overline{A^T}=\bar{A}^T$.
For example, if $A=\left(\begin{array}{cc}1+\mathrm{i} & 2 \mathrm{i} \\ -3 & 2-5 \mathrm{i}\end{array}\right)$, then $A^{\dagger}=\left(\begin{array}{cc}1-\mathrm{i} & -3 \\ -2 \mathrm{i} & 2+5 \mathrm{i}\end{array}\right)$. Prove that
(a) $\left(A^{\dagger}\right)^{\dagger}=A$,
(b) $(z A+w B)^{\dagger}=\bar{z} A^{\dagger}+\bar{w} B^{\dagger}$ for $z, w \in \mathbb{C}$,
(c) $(A B)^{\dagger}=B^{\dagger} A^{\dagger}$.