Question
The Hof of TiI3(s) is -328 kJ>mol, and the H for the reaction 2 Ti(s) + 3 I2(g) 2 TiI3(s) is -839 kJ. Calculate the H of sublimation (the state transition from solid to gas) of I2(s), which is a solid at 25 C.
Step 1
This corresponds to the reaction: \[2 \, Ti(s) + 3 \, I2(s) \rightarrow 2 \, TiI3(s)\] The heat of this reaction is -656 kJ (since -328 kJ/mol * 2 mol = -656 kJ). Show more…
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The $\Delta H_{\mathrm{f}}^{\circ}$ of $\mathrm{TiI}_{3}(s)$ is $-328 \mathrm{kJ} / \mathrm{mol},$ and the $\Delta H^{\circ}$ for the reaction $2 \mathrm{Ti}(s)+3 \mathrm{I}_{2}(g)$ $\longrightarrow 2 \mathrm{TiI}_{3}(s)$ is $-839 \mathrm{kJ}$. Calculate the $\Delta H$ of sublimation (the state transition from solid to gas) of $\mathrm{I}_{2}(s),$ which is a solid at $25^{\circ} \mathrm{C}$ .
The ΔH∘f of TiI3(s) is -328 kJ/mol and the ΔH∘ for the reaction 2Ti(s) + 3I2(g) → 2TiI3(s) is -839 kJ. Calculate the ΔH of sublimation of I2(s), which is a solid at 25 ∘C.
The $\Delta H_{\mathrm{f}}^{0}$ of $\mathrm{TiI}_{3}(s)$ is $-328 \mathrm{~kJ} / \mathrm{mol}$ and the $\Delta H^{\circ}$ for the reaction $2 \mathrm{Ti}(s)+3 \mathrm{I}_{2}(g) \longrightarrow 2 \mathrm{TiI}_{3}(s)$ is $-839 \mathrm{~kJ} .$ Calculate the $\Delta H$ of sublimation of $\mathrm{I}_{2}(s)$, which is a solid at $25{ }^{\circ} \mathrm{C}$.
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