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Eugene S.
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Problem 112 Hard Difficulty

The Hof of TiI3(s) is -328 kJ>mol, and the H for the reaction 2 Ti(s) + 3 I2(g) 2 TiI3(s) is -839 kJ. Calculate the H of sublimation (the state transition from solid to gas) of I2(s), which is a solid at 25 C.

Answer

$$
61 \mathrm{k} \mathrm{J} / \mathrm{mol}
$$

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Video Transcript

So in this question were given the chemical formula to t I solid plus three eye to gas forms to ti I I three solid and that has a delta h of negative eight thirty nine killer Jules. Oh, and then we're also given the Delta h of formation off t I three. So that would equal to t i solid plus three. I too solid this time forms to ti I I three solid and then we take our delta h not of formation and multiply it by two. And so negative three, twenty eight times two equals negative six fifty six killer Jules promote. And so now we want to subtract these equations and then we can also subtract. They're adults ages. And so doing this we end up with three eye to gas minus three. I too solid forms no product and ah, then we get our delta h for this is one eighty three killer Jules Permal. And so now that we have this, we can take our heat of sublimation which should be solid to gas. And we just take our delta h from the reaction and divide it by three. So we get that our adult age of sublimation is going to be sixty one killer Jules Permal, and that will be our final answer.

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