0:00
Hi, everybody.
00:01
So we need to determine the mass moment of inertia of the cylinder with respect to line joining.
00:08
So we have this image here, which i'm going to try to kind of draw.
00:19
So we have height.
00:24
This is z, by the way.
00:26
This is x.
00:27
This is y.
00:31
We have a.
00:33
And actually, and let me shorten this a little bit because we need this guy to niche about there.
00:42
There we go.
00:45
This is supposed to be curving down.
00:48
So let me just clean that up.
00:56
So we have a and at this point we have zero.
00:59
Okay.
01:01
Looks good.
01:02
So now what we can do is i -x equals i -y -z.
01:11
There we go.
01:13
And so for the circular cylinder, your i, y, is going to equal to one half m .a squared, by the way.
01:25
So for this right here, we have one half m3a squared plus height squared plus m height squared.
01:41
Square, okay? and we're just going to simplify this.
01:45
So one half.
01:47
M.
01:49
3a squared plus h squared plus 3h squared plus 3h squared...