The horizontal range of a bullct, when fircd at 45^∘, is 1200 m. If it is fired from a lorry, m

step 1 Hello students in this question this is a projectile motion and in which only the vertical compo

The horizontal range of a bullct, when fircd at 45^∘, is...

The horizontal range of a bullct, when fircd at $45^{\circ}$, is $1200 \mathrm{~m}$. If it is fired from a lorry, moving at $24 \mathrm{~km} / \mathrm{h}$ with the same velocity and clevation, then find its range. (Take $\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2}$ )

Key Concepts

Vector Addition of Velocities

The process of vector addition allows the combination of different velocity components to determine the resultant velocity. In projectile motion from a moving platform, the horizontal component of the projectile’s launch velocity is added to the platform’s velocity, effectively changing the starting conditions of the projectile’s motion. This is an essential concept for analyzing motion in non-inertial reference frames.

Relative Velocity and Moving Reference Frames

When a projectile is launched from a moving platform, its effective initial velocity relative to a stationary observer is the vector sum of its velocity relative to the platform and the platform's velocity. This concept of relative velocity is crucial in determining how the additional motion of the platform affects the overall trajectory and range of the projectile.

Projectile Motion

Projectile motion describes the trajectory of an object when it is thrown or projected into the air, subject only to the acceleration of gravity. This concept involves analyzing both horizontal and vertical components of motion independently, with gravity affecting only the vertical motion while the horizontal motion remains constant in the absence of air resistance.

Horizontal Range Formula

The horizontal range of a projectile is the total distance it travels along the horizontal axis. Typically, when launched from level ground at an angle, the range is given by the formula R = (u² sin(2?)) / g, where u is the initial speed, ? is the launch angle, and g is the acceleration due to gravity. This formula is key to understanding how launch speed and angle influence the projectile’s reach.

Transcript

Please give Ace some feedback