Question
The increasing order of nucleophilicity of the following nucleophiles is:(i) $\mathrm{CH}_{3} \mathrm{CO}_{2}^{-}$(ii) $\mathrm{H}_{2} \mathrm{O}$(iii) $\mathrm{CH}_{3} \mathrm{SO}_{3}^{-}$(iv) $\mathrm{OH}$(a) $(\mathrm{i})<(\mathrm{iv})<(\mathrm{iii})<(\mathrm{ii})$(b) $($ ii $)<($ iii $)<($ iv $)<($ i)(c) $(\mathrm{iv})<(\mathrm{i})<(\mathrm{iii})<(\mathrm{ii})$(d) $($ ii $)<($ iii $)<($ i $)<$ (iv)
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Molecules with a negative charge have a higher tendency to donate electrons and hence have higher nucleophilicity. Show more…
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Consider the following nucleophiles: $\mathrm{H}_{2} \mathrm{O}, \quad \mathrm{CH}_{3} \mathrm{COO}^{-}, \quad \overline{\mathrm{O}} \mathrm{H}, \quad \mathrm{CH}_{3} \mathrm{O}^{-}$ $\begin{array}{llll}\text { I II II I } & \text { II } & \text { III } & \text { IV }\end{array}$ The correct order of decreasing nucleophilicity is, (a) $\mathrm{I}>\mathrm{II}>\mathrm{III}>\mathrm{IV}$ (b) IV $>\mathrm{III}>\mathrm{II}>\mathrm{I}$ (c) IV $>\mathrm{I}>\mathrm{II}>\mathrm{III}$ (d) IV $>\mathrm{II}>\mathrm{III}>\mathrm{I}$
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Relative stabilities of the following carbocations will be in the order (a) $\mathrm{i}<\mathrm{ii}<\mathrm{iii}<\mathrm{iv}$ (b) iv $<\mathrm{iii}<\mathrm{ii}<\mathrm{i}$ (c) $\mathrm{iv}<\mathrm{ii}<\mathrm{iii}<\mathrm{i}$ (d) $\mathrm{ii}<\mathrm{iv}<\mathrm{iii}<\mathrm{i}$
General Organic Chemistry
Level I
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