00:01
Okay, so for this one, we're given that you have inductors in the following configuration.
00:11
And then here's l1, l2, l3, and l4.
00:20
And then the goal is to get the equivalent inductance using the previous two problems, which gives you the results that for parallel inductors, you can add them inversely.
00:29
And then for series inductors, you can add them just regularly.
00:34
L1 plus l, l equivalent is l1 and l2.
00:37
So i'd review those problems if you haven't already or if you're not sure what i mean.
00:42
And so l2 and l3 are in parallel.
00:44
So you can say 1 over l equivalent to 3 is equal to 1 over l2 plus 1 over l3.
00:54
And then if you solve for the equivalent for this, maybe you'll get what i got, which is kind of combine these fractions and then flip the fractions, that's going to be l3 times l2, all divided by l2 plus l3.
01:13
And then now you have the network of two and three in series with one and four...