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The infamous chicken is dashing toward home plate witha speed of 5.7 $\mathrm{m} / \mathrm{s}$ when he decides to hit the dirt. The chickenslides for 1.2 $\mathrm{s}$ , just reaching the plate as he stops (safe, of course).(a) What are the magnitude and direction of the chicken's acceleration? (b) How far did the chicken slide?

(a) $a=-4.75 \mathrm{m} / \mathrm{s}^{2}$ in the direction of plate to chicken(b) 10.22 $\mathrm{m}$

Physics 101 Mechanics

Chapter 2

One-Dimensional Kinematics

Motion Along a Straight Line

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route. This problem. We have a chicken with velocity off speed of velocity, but five point seven meters per second. Ah, chicken slides for a time. 1.2 seconds. And the problem wants to know what was the magnitude indicted action off the deceleration and how far the chicken slide. Okay, first of all, that's calculates the deceleration. We know that the only thing the only information we have about the problem is the velocity in time. And there is this equation. They're relates velocity. It was a function off time. So we're going to use desecration to calculate the acceleration first. So let's see. The final velocity to is zero because that you can stops. The initial velocity is 5.7 less acceleration. We want a calculated times 1.2 seconds gay. So acceleration is going to be minus 5.7, divided by 1.2. So this is going to be for 0.75 minus 4.75 Okay, so first answer, the magnitude magnitude is always positive values. So the positive value off the acceleration is going to be four point seven five meters 1st 2nd square and the direction is going to be direction. Let's see. Going to be they believed. Wait. Two chicken. If the chicken is here, she killed the fleet is here. The direction of this deceleration is going to be this one. Okay, so let's see this second light and we want to calculate the distance to calculate the distance we're just going to use is a creation that relates velocity with distance plus two. Hey, out x Final velocity zero Because he stops you nish your velocity. 5.7 square miners minus true times acceleration that receive in here it was 4.75 or 0.75 times displacement. Okay, so let's calculate this. So we have then minus 32 point for nine. You find it by minus two times or 0.75 This is equals two distance. Could the minus sign so the distance is equals two three point for two meters. This is the final answer. A fortune

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