00:01
Okay, so for this question, they want us to calculate the final temperature.
00:05
So they give us the initial temperature as 18 .2 degrees celsius, the mass as 344 grams, and q as 2 .25 kilojoules.
00:18
And the sample that we have is iron.
00:20
And when we look up the specific heat capacity of iron, we get, so we have c is equal to 0 .449 joules.
00:30
Program times kelvin right so the first thing that we're gonna do is we gotta convert this celsius to kelvin because of this all so celsius all we got to do is add 273 and we get kelvin and we should get 291 .2 kelvin now uh for q we got to convert this into jewels because we see the specific heat capacity as jewels so all we're going to do is multiply this by a thousand because one kilojoules is equal to a thousand joules, right? we get 2 .25 times 10 to the third joules.
01:13
Now all we need to do is plug this into this equation right here.
01:16
Q is equal to c, which is the specific heat capacity times it by the mass, times it by delta t...